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Physics Problem Solver Online

Gravity helps us to keep our feet on the ground, and these amazing physics problem solvers will help you hold your head up high. No more difficulties with concepts of Physics! The immediate help is here. Mainky because every student who chooses to study physics correctly and in-depth occasionally needs the access to useful online resources that may act as a guide for their academic journey. In this post we will go through the list of them and discuss the advantages of how it works.

TOP 3 physics homework help sites where you can solve your problems right away:


Free Physics Calulators


Top 3 Physics Apps For Students

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—> 15 Best Physics Apps For iOS

Physics Problem Solver for Homework Help

The ideal physics problem solver will give you the solutions of problems in a variety of branches. No matter which feature you decide to use, this will be a very simple and quick task. You just need to enter the required information. When you have several fields, you have to check carefully which parameter goes where. As long as you enter everything correctly, you will get the correct answer. It pays off to double check before you click on the submission button. Make sure that you get good understanding of the solution. This will help you to prepare perfectly for exams.

Physics Homework Help to Prop up your Grades in School

Homework given at schools is never a cause for joy for the students, even those who are good in studies. However, there are subjects in humanities that prove to be much easier for students when it comes to doing their homework. After all, you do not solve numerical applying formulae when asked to do the assignment at home in language or History. But the same is not the case with homework given in science subjects, especially physics. Even though it is a very interesting subject that explains the way things in the world around us work, most students dread mastering the theories and their applications in real life. These students look for physics homework help to complete their assignments in time as otherwise they lose important marks and grades in the final exam.

Online help with your problems is a very effective method

Internet has emerged as information super highway for people around the world. Availability of fast speed internet in homes across the country has helped students greatly as they can now receive physics homework help sitting in the comfort of their own home rather than having to go to a coaching center or call in a tutor at home. Both these options are costly proposition in present times. In contrast, registering yourself with any of the many websites providing online help to students proves to be not only inexpensive but also very convenient way of receiving help in completing your physics homework.

Get answers on time to submit assignments on time

You cannot remain dependent upon your school science teacher to look after your specific problems in Physics as he has to complete the syllabus in a short time period. He therefore explains the chapters in Physics at his usual pace and expects that all students will grasp the concept. If you are not attentive or fail to understand a concept, you will need help from an expert to make the concept clear for you. This is necessary as otherwise you cannot solve problems based upon that principle. Websites solving the problems of students claim to have cracked thousands of text books to provide quick and efficient physics homework answers in a quick time. You can post a question on the website at any time of the day and also expect it to be answered by the expert teachers in as little as 2 hours time.

You can get this online help sitting in the comfort of your own home any time of the day. This is really great as you can get answers to questions given by your teacher at school as homework. This is only the start as you find that explanations given by teacher on these websites slowly and gradually start to make the concepts clear to you. This is really helpful as it goes a long way in mastering physics homework solutions on your own. Yes, as time passes and you receive continuous help from online teacher, you become proficient in Physics and become able to solve the problems on your own.

There are many reasons why students do not do well in their homework, and many reasons why they need physics homework help. The most common reason is that they find it difficult to understand some of the formulas and theories in physics. This is why they look for physics homework help. There are many sites on the internet that offer help with homework in physics. However, if you are really serious about studying and doing well in this subject, you should look for a reliable physics homework help site, that offers help from real experts at a reasonable price. All such sites offer physics homework help online, and this is the way to go, as the physics homework help online is done by real experts and teachers, and the students can get instant answers to all their questions and doubts. They can get help with their homework in physics on subjects like thermodynamics, mechanics, electromagnetism, and optics, and other branches of physics.

Apart from giving physics homework help online, these sites also offer other services to students. They can prepare physics homework online, and also can prepare for their physics exams online. They can also get interactive help from the experts at these sites, and this is very effective, as the students can then ask questions in a language of their own, and the experts will help them understand the answer. It is always good to take help from experts without burning a hole in your pocket.

There are several other benefits of using physics homework help online. If you are a student of any class, and are struggling to do your homework in physics for some reason, you can take help from experts. There are many companies that offer physics homework help online, and you can get the best services from any of them. However, you need to choose a site that has experts who are qualified and have years of experience in providing such services. You need to choose a site that will provide you with the best help with physics homework at the best price.


  • All I can understand from physics is that there are some particles that make up everything we see and the smart guys are trying to combine the 4 forces of physics into one universal theory. I think this is the most my brain can process. Thanks for this collection though. Helps me doing my homework without a clear understanding of what I’m doing.

  • Question#2: The electrostatic force between two identical ions that are separated by a distance of 5.0 x 10-10 m is 3.7 x 10-9 N. (a) Find the charge on each ion. (b) How many electrons are missing from each ion?

    please anyone help me

  • I have two towers and both of them are 10cm long and they are connected by a rope that is 15m long and the distance between the rope and the ground is 2.5m long , what is the distance from the first tower to the second tower? HELP ME PLEASE

    • 1. Determine the tension in each of the ropes holding the object. Rope T1 is at an angle of 60 degrees, rope T2 is at an angle of 55 degrees, the suspended block has a mass of 300kg. 2. w = mg 3. 300kg * 9.8 m/s = 2940 N, or the weight of the block, but since this I’ve just divided the weight by the sin of each rope’s given angle. Completely baffled and very tired, looking for a push in the right direction so my brain can worky again. The answers are: T1 = 1862 N , T2 = 1620 N but I have no clue how to arrive at them

  • 1. an object is dropped from a point at a height of 750 meters. What is the time and velocity when the object reached the ground?

    2. A ball was thrown horizontally with a speed of 60 ft/sec on the top of a building with a height of 50 meters. How far from the base of the building did the ball hit the ground? What is the velocity, magnitude, and direction 4 seconds after it was thrown?

    3.A small weight is tied at the end of a string 3 ft long and revolves 13 times in 2 seconds. What linear distance has the weight traveled? How many radians does it make in 1 second?

    4. A wheel with 25 cm radius starts from rest and rotates about a horizontal axis through the center with a constant angular acceleration of 0.8 radian/sec^2. A point in the circumference is directly at the right of the center of the wheel. At the end of 2 seconds,
    a) find the angular displacement of the point,
    b) the radial acceleration,
    c) tangential acceleration and
    d) the resultant acceleration.


    5) The weight of a ladder resting on a wall and a floor is 78 lbs. If the total length of the ladder is 16 ft. and it is inclined 57 degrees with the horizontal. Find the magnitude and direction of the resultant, F, exerted by the floor on the ladder.

    6) A body weighing 60 lbs in on a horizontal plane. If the coefficient of static friction is 0.22, what horizontal force will start the body? What parallel force to the horizontal will keep the body moving uniformly if the coefficient of kinetic friction is 0.192?

    7) A body slides down on the slide when it is inclined 30 degrees. What is the coefficient of friction between the boy and the slide?

    8)An automobile traveling at a speed of 60 km/hr is brought t orest by means of the brakes in a distance of 89 meters. What is the average acceleration?

    • COnsider a Cubical box of length L. And a positive charge q is placed inside the cubical box . Find the net Flux???????

  • A person swims @ a velocity of 3.6 m/s N 20′ E. The current of the water is flowing at the speed of 1.8 m/s S 80’E. What is his true velocity and how do I find it with trig

  • A person swims at 5 m/s W30’S for 20mins. He then swims at 6 m/s N20’W for 15 mins, what is his displacement and what is his average velocity? How to solve w components please

  • Kinematic 2 Dimension (Vector)

    Here is the question…

    Position of squirrel in a park is given by :
    r =[(0,280 m⁄s)t+(0,0,036 m⁄s^2 ) t^2 ] i ̂+(0,0190 m⁄s^3 ) t^3 (j.) ̂

    Find ;
    1. Vx(t) dan Vy(t) ??
    2. t = 5,00 s, how far from the starting point position is squirrel moving ?
    3. t = 5,00 s, how fast the squirrel moving and define its direction?

  • When a family of four with a total mass of 200 kg step into their 1200-kg car, the car’s springs compress 3.0 cm.
    a)What is the spring constant of the car’s springs, assuming they act as a single spring?
    b)How far will the car lower if loaded with 300 kg rather than 200 kg?

  • Assume the shock absorbers of a car are very poor. poor, so the car really oscillates up and down when hitting a bump. Determine the period and frequency of a car whose mass is 1400 kg and whose shock absorbers have a spring constant of 6.5 x 104 N/m after hitting that bump.

  • A large motor in a factory causes the floor to vibrate at a frequency of 10 Hz. The amplitude of the floor’s motion near the motor is about 3.0 mm.
    Estimate the maximum acceleration of the floor near the motor.

  • The cone of a loudspeaker oscillates in SHM at a frequency of 262 Hz (“middle C”). The amplitude at the center of the cone is A = 0.15 x 10-3 m, and at t = 0, x = A.
    a) What equation describes the motion of the center of the cone?
    b) What are the velocity and acceleration as a function of time
    c) What is the position of the cone at t = 1.00 ms?

  • For the simple harmonic oscillation of a spring where: Spring constant k = 19.6 N/m,
    Max. amplitude of the system: A = 0.100 m Start condition: x = -(0.100 m)
    Angular frequency: ω = 8.08/s
    Max. speed of a mass connected to the spring: 
vmax = 0.808m/s
    a) the total energy

    b) the kinetic and potential energies as a function of time

    c) the velocity when the mass is 0.050 m from equilibrium
    d) the kinetic and potential energies at half amplitude

    (x = ± A/2)

  • An unfortunate accident occurred on the toll way. A driver accidentally passed through a faulty barricade on a bridge (quite unfortunately). and landed in a pile of hay (quite fortunately). Measurements at the accident scene reveal that the driver plunged a vertical distance of 8.26 meters. The car carried a horizontal distance of 42.1 meters from the location where it left the bridge. What was the driver’s speed (in mi/hr – do not enter units)? Assume that the contact with the barricade did not slow the car down. (1.00 m/s = 2.24 mi/hr)

  • A cannonball is launched from the top of a 125-meter high cliff with an initial horizontal speed of 20 m/s. How far horizontally did the cannonball travel in the first 2s?

  • A balloon is moving up from the ground in such a way that its acceleration is linearly decreasing
    with its height above the ground. It starts from the ground with acceleration 4 m/ s2
    and with zero
    initial velocity. Its acceleration becomes zero at a height 3 m. The speed of the balloon at a height
    1.5 m is ……
    can you give me the answer please?????????????????????

  • a bicycle driver covers 90 km with average speed equals 36 km/h but he covers the first 30 km in 2 hours .Calculate the Speed in which
    the remaining distance is covered.

  • 15 meter focas duri wale uttal lans se 20 meter dur and 1meter lambi 1pancil rakhi hai pancil k pratibimb ki sthiti prakriti and lambai kya hogi

  • The half life of radioisotope is 10 hrs. Find the total number of disintegration in the tenth hour measured from a time when the activity is 1 Curie.

  • You push your physics book 1.50m along a horizontal tabletop with a horizontal push of 2.40N while opposing force of friction is 0.600N. How much does each of the following forces do on your book
    (i) your 2.40N push
    (ii)the frictional force
    (iii) the normal force from the tabletop and
    (iv) gravity
    (v) what is the net work done on the book?

  • A bullet is fired from the back of a pick up truck that is 1meter above the ground. The gun is shot at a 60 degree angle at an initial velocity of 200 meters per second. What is the range of the bullet? What is the maximum height that the projectile reaches?

  • Turn three at the Talladega speedway has a radius of 254m and is banked at an angle of 33 degrees from the horizontal.
    a. Draw a force diagram for a 60kg driver on the turn.
    b. At what speed could the driver take the turn without steering?
    c. What is the magnitude of the force of the seat on the driver?
    d. How would he feel?

  • calculate the force needed to hold a 1000kg car in arc of radious 10metre when the car is turning a corner at 10meter per seconds? please i need help in okeke physics text book sss 2

  • 1. Explain the statement
    a. Metallic bond is an unsaturated covalent bond.
    b. Ionic bond is unsturated and non – directional.
    2. Using the f – r curve explain how you would.
    a. Find the force constant k (form f=-kx)where x is the extension of a wire in the elastic region.
    b. Account for hook’s law of elasticity
    c. Obtain the value for the breaking force of a solid

  • How much heat is required to raise the temperature of 100g of water from 10’C to 25’C? (The specific heat of wateris 4180 J/ Kg/ K)

    • I get two answers for this but i don’t know which is correct. The only difference in both of my methods lies in the conversion of Celsius to Kelvin.
      Q = m*c*rise in temperature
      m=0.1kg ; c=4180 J/Kg/K ; rise in temperature= 25’C-10’C=15’C=288K
      Q= 0.1*4180*288
      = 120,384 J

      second method is :
      Q= m*c*rise in temperature
      m=0.1kg; c=4180 J/Kg /K; rise in temperature= (273+25) – (273+10) = 298-283= 15K
      Q= 0.1*4180*15
      =6,270 J

      • Hey, your first method is incorrect, because you can’t convert change of the temperature to direct temperature (it doesn’t matter if it’s Kelvin or Celsius, the change will be the same number, since you have to apply 273 before calculation, not after it), your second method is correct, because the change is 15 degrees (both in Kelvin and Celsius, since 25-10 = 15 and 298-283 = 15).

    • Explanation:
      You can find the amount of heat needed to increase the temperature of your sample by

      by using the equation

      q=mxcx triangle time

      is the heat lost or gained by the substance
      is the mass of the sample
      is the specific heat of the substance
      is the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

      Now, the trick here is to realize that the mass of the sample is given to you in grams, but that the specific heat of water is expressed in joules per kilogram Celsius.
      This means that you will have to convert the mass of the sample from grams to kilograms by using the fact that

      1kg=10^3 g

      100 g x 1kg/10^3=0.1 cross “gram and gram

      Now you’re ready to plug your values into the equation and solve for

      q=0.1 kg.4,181 J kg^-1 C^-1 . 50 C= q 21,000 j

  • A duck of mass 2,5 kg paddles and a force of 0,2N acts on it.current of water exerts a force of 0,2N in a direction of 52degrees SE .the velocity of the duck is 0,11m/s find size of displacement that the duck undergoes in 3s

  • We will model the behaviour of elastic arteries as they expand with each heartbeat, and store energy. Assume a radius of r at the lower diastolic pressure P1, and length L, and an inner surface area A for this cylindrical section. The blood pressure exerts a force F1 on that surface area, and when the pressure increases to P2 (systolic) the force increases to F2 and the radius increases to r + x.
    (a) Sketch a graph of force on the blood vessel surface A versus x, the increase in radius. Mark and label a quantity corresponding to elastic potential energy due to increased blood pressure.
    (b) Estimate this energy when the diastolic and systolic pressures are 10 kPa and 16 kPa, respectively, L = 27 mm, r = 5.1 mm, and the increase in radius x = 0.5 mm.

  • A stone is thrown vertically upward with an initial speed u from the top of a tower , reachesthe ground with a speed 3u.Find the heightof the tower.

    • First let us check the approximate position of the stone.
      Time to reach highest point:
      Putting v=0, a=-g we get
      Thus the stone will still be in the air on its way back to the ground at t=4u/3g
      Distance traveled by going to highest point,
      Distance traveled going down,
      x = ut + (1/2)at^2
      Putting u=0 (coming down from top), t=4u/3g-u/g = u/3g (time elapsed after reaching the top) and a=g you get x.

      Thus total distance = h + x

  • A hollow charged metal sphere has a radius r if the potential difference between its surface and a point at distance 3r from its center is V then electric intensity at distance 3r from the center

  • A load W hangs from a rope connected to two separate ropes that are attached to the wall and ceiling at the angles: T1: 75° and T2: 56°. If the weight of the object is 100N, find the magnitudes of the tensions T1 and T2.

  • Can anyone help me about this problem? ” Convert 400 in.3/day to cm 3/min”. Please help me. I’m not good at that.

  • Daisy and Rema made a circuit. They turned on the switch but the electricity did not flow, bulb did not lit up even though electrical wires were connected properly. Give possible reasons why their circuit did not work when they close the switch.
    please help

  • The position of a particle moving along the x axis varies in time according to the expression x=4t^2 , where x is in meters and t is in seconds. Evaluate its position at the following times. (A) t= 3.40s (B) t=3.40s + delta t (C) evaluate the limit of delta x/delta t as delta t approachs zero to find the velocity at t=3.40s.

  • A 51.0-g Super Ball traveling at 30.0 m/s bounces off a brick wall and rebounds at 21.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 4.90 ms, what is the magnitude of the average acceleration of the ball during this time interval?

  • I am not sure but I think it is proportional to KE or kinetic energy which means it would be 9 times larger. 3^2

    24. C velocity increases and acceleration remains unchanged. When you drop something it will accelerate at 32.2 ft/s^2. After two seconds the object is travelling at 64.4 ft/s so velocity is increasing which is the definition of acceleration.

    25. It is important to distinguish here between momentum P1V1 = P2V2 and kinetic energy or KE = (1/2) mv^2. B 1/3 3 x 1/3 = 1 x 1

    33. The circumference is proportionate to the radius which is twice as long so the centripetal acceleration should be half as much. B

    34. 1 N = 1kg-m/s^2 thus 500 kg-m/s^2 x 7s x 1/20kg = 175 m/s. Note that the units cancel. This is called dimensional analysis.

  • the defender on a football team kicks a ball 47.4 meters down field it takes 7.4 seconds to hit the ground what angle was the ball kicked

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